A bag contains a red ball, a blue ball and a yellow ball, all the balls being of the same size.
Kritika takes out a ball from the bag without looking into it. What is the probability that she
takes out the
(i) yellow ball?
(ii) red ball?
(iii) blue ball?

The number of possible outcomes = Number of balls in the bag = n(S) = 3.
(i) The number of outcomes favourable to the event Y = n(Y) = 1.
So, P(Y) = n(Y)/n(S) =1/3Similarly,
(ii) P(R) = 1/3and
(iii) P(B) = ⅓

A box contains 80 discs which are numbered from 1 to 80. If one disc is drawn at random
from the box, find the probability that it bears a perfect square number.

Total number of outcomes = 80
Perfect square numbers from 1 to 80 = 1 ,4, 9, 16, 25, 36, 49, 64
Therefore, favourable outcomes = 8
Probability of getting a perfect square number = 8/80 = 1/10.

The median of the following data is 525. Find the missing frequency ‘x’
Find the modal height.

2×11 Table
Class0- 100100 -200200 -300300 -400400-500500-600600-700700-800800-900900-1000
Frequency25X12172015974

n=100, 76+x+y=100, x+y=24, given median is 525. Median class 500-600 I=500, h=100,
f=20, cf=36+x

525= 500+50−(36+𝑥)/ 20 ∗ 100 Simplifying we get x=9 and y=15

Find mode of the following distribution

2×11 Table
Class25-3535 -4545 -5555 -6565-7575-85
Frequency7313317111

46.11

Find the mean of the following data

2×11 Table
ClassLess than 20Less than 40Less than 60Less than 80Less than 100
Frequency15377499120

=>52.5

If the mean of the following data is 18.75. find the value of P.

2×11 Table
xi1015P2530
fi510782

P=20

Determine the missing frequency x, from the following data, hwn Mode is 67

Class40-5050-6060-7070-8080-90
Frequency5x15127

x=8

The following data gives the information observed life times (in hours) of 225 electrical components. Determine the modal life times of the components.

Life time
(inhours
0-2020-4040-6060-8080-100100-200
Frequency103552613829

=65.625 hours

Find the median of the following data:

MarksFrequency
Less than 100
Less than 3010
Less than 5025
Less than 7043
Less than 9065
Less than 11087
Less than 13096
Less than 150100

76.36

The median of the distribution given below is 14.4. Find the values of x and y, if
the sum of all the frequencies is 20.

Class interval0-66-1212-1812-2424-30
Frequency4X5Y1

X=4 and Y=6

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