Following is the distribution of marks obtained by 60 students in science test

MarksNo.of Students
More than 060
More than 1056
More than 2040
More than 3020
More than 4010
More than 503

Mean = 26.5

If mode of data is 23/7 , then find x and y

Class1-33-55-77-99-11Total
FrequencyX8Y2120

X= 7 and y= 2

Bowling strike rate for a bowler is defined as the average number of balls bowled per wicket
taken. A bowler has taken 148 wickets so far with a strike rate of 27. In his next match, he
bowls 48 balls and takes 2 wickets.
What is his new strike rate? Show your work.

Find the total number of balls bowled by the baller so far as 148×27=3996
Finds the total number of balls bowled after the last match as 3996+48=4044.
and the total number of wickets taken after the latest match as 148+2=150.
Find the new strike rate of the bowler as (total number of balls bowled)/(total number
of wickets taken) = 4044/150 = 26.96

The frequency distribution of daily rainfall in a town during a certain period is shown below

Rainfall (in mm)Number of days
0-207
20-40X
40-6010
60-804

Unfortunately, due to manual errors, the information on the 20-40 mm range got deleted from
the data.
If the mean daily rainfall for the period was 35mm, find the number of days when the rainfall
ranged between 20-40 mm. Show your work

the value of x as 23.

If the mean of the following distribution is 6, find the value of‟p‟.

x24610P+6
y32312

. P = 7

Find the median of the following data:

Wages(Rs)No of workers
More than 150nill
More than 14012
More than 13027
More than 12060
More than 110105
More than 100124
More than 90141
More than 80150

= 116.67

If mode of the following frequency distribution is 55, then find the value of x

ClassFrequency
0-1510
15-307
30-45X
45-6015
60-7510
75-9012

Mode=55 , So Modal class= 45-60
Mode = l +[(f1-f0)/(2f1 –f0 –f2 )] x h
Or,55 =45 + 15x(15-x)/(2×15-x-10 )
Or, 55 = 45 + (225- 15x)/ 30-x-10
Or, 55(20-x) = 45(20-x) +225-15x
Or,1100 – 55x = 900 -45x +225 -15x
Or, 5x=1125-1100
x=5

SELF ASSESSMENT

Q1. The mean of the following frequency distribution is 25. Find the value of f

Class0-1010-2020-3030-4040-50
Frequency51815f6

Q2. The mean of the following data is 18.75. Find the value of P

Class MarkFrequency
105
510
P7
258
302

Q3. Following table shows sale of shoes in a store during one month

Size of shoesPairs of shoes sold
34
418
525
612
75
81

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